reverse3
0x01
Exeinfo PE Check
32位 无壳
0x02
IDA
分析主函数 main_0()
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| int __cdecl main_0(int argc, const char **argv, const char **envp) { size_t v3; const char *v4; size_t v5; char v7; char v8; signed int j; int i; signed int v11; char Destination[108]; char Str[28]; char v14[8];
for ( i = 0; i < 100; ++i ) { if ( (unsigned int)i >= 0x64 ) j____report_rangecheckfailure(); Destination[i] = 0; } sub_41132F("please enter the flag:", v7); sub_411375("%20s", (char)Str); v3 = j_strlen(Str); v4 = (const char *)sub_4110BE(Str, v3, v14); strncpy(Destination, v4, 0x28u); v11 = j_strlen(Destination); for ( j = 0; j < v11; ++j ) Destination[j] += j; v5 = j_strlen(Destination); if ( !strncmp(Destination, Str2, v5) ) sub_41132F("rigth flag!\n", v8); else sub_41132F("wrong flag!\n", v8); return 0; }
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追踪sub_4110BE()
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| int __cdecl sub_4110BE(int a1, int a2, int a3) { return sub_411AB0(a1, a2, a3); }
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追踪 sub_4110BE()
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| void *__cdecl sub_411AB0(char *a1, unsigned int a2, int *a3) { int v4; int v5; int v6; int v7; int i; unsigned int v9; int v10; int v11; void *v12; char *v13;
if ( !a1 || !a2 ) return 0; v9 = a2 / 3; if ( (int)(a2 / 3) % 3 ) ++v9; v10 = 4 * v9; *a3 = v10; v12 = malloc(v10 + 1); if ( !v12 ) return 0; j_memset(v12, 0, v10 + 1); v13 = a1; v11 = a2; v4 = 0; while ( v11 > 0 ) { byte_41A144[2] = 0; byte_41A144[1] = 0; byte_41A144[0] = 0; for ( i = 0; i < 3 && v11 >= 1; ++i ) { byte_41A144[i] = *v13; --v11; ++v13; } if ( !i ) break; switch ( i ) { case 1: *((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2]; v5 = v4 + 1; *((_BYTE *)v12 + v5) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))]; *((_BYTE *)v12 + ++v5) = aAbcdefghijklmn[64]; *((_BYTE *)v12 + ++v5) = aAbcdefghijklmn[64]; v4 = v5 + 1; break; case 2: *((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2]; v6 = v4 + 1; *((_BYTE *)v12 + v6) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))]; *((_BYTE *)v12 + ++v6) = aAbcdefghijklmn[((byte_41A144[2] & 0xC0) >> 6) | (4 * (byte_41A144[1] & 0xF))]; *((_BYTE *)v12 + ++v6) = aAbcdefghijklmn[64]; v4 = v6 + 1; break; case 3: *((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2]; v7 = v4 + 1; *((_BYTE *)v12 + v7) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))]; *((_BYTE *)v12 + ++v7) = aAbcdefghijklmn[((byte_41A144[2] & 0xC0) >> 6) | (4 * (byte_41A144[1] & 0xF))]; *((_BYTE *)v12 + ++v7) = aAbcdefghijklmn[byte_41A144[2] & 0x3F]; v4 = v7 + 1; break; } } *((_BYTE *)v12 + v4) = 0; return v12; }
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综上特征:发现这是一个 base64 加密
追踪 str2
1
| .data:0041A034 00000011 C e3nifIH9b_C@n@dH
|
0x03
编写逆向 EXP
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| import base64
str1 = 'e3nifIH9b_C@n@dH' str2 = ''
for i in range(len(str1)): str2 += chr(ord(str1[i])-i)
print(base64.b64decode(str2))
|
完整的 flag 为 flag{i_l0ve_you}